By Ron Liskey | Earth Date: December 18, 2020 CE
Write the following sum as a simple fraction in lowest terms.
$$ \dfrac{1}{1 \times 2} + \dfrac{1}{2 \times 3} + \dfrac{1}{3 \times 4} + \dfrac{1}{4 \times 5} + \dfrac{1}{5 \times 6} = $$
All but two of the terms cancel out. Why, and what’s left?
$$1 – \dfrac{1}{6} = \dfrac{5}{6}$$